Question

If sinx+cosec x=2,then sin ^-13x-cosec^-17x+3 is

Answer 1

Answer:

Given

$sin \: x + \frac{1}{sin \: x} = 2$

i.e Sin x = 1

now, putting value of Sin in question..

$sin {}^{ - 13} x - \frac{1}{sin {}^{ - 17} x} + 3 = {1}^{ - 13} - \frac{1}{ {1}^{ - 17} } + 3 = 1 - 1 + 3 = 3 \: ans.$

Thanks.