If sinx+cosecx=2, find the value of sin^2x+cosec^2x
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Answered by
4
Step-by-step explanation:
We have to find
sin²x + cosec²x
=(sin x + cosec x) ² -2sinx × cosecx
=2² - 2
=2
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Answered by
2
● Here ,
given value is
■ sinx + cosecx = 2
sin^2x + cosec^2x
= (sin x + cosecx)^2 - 2sinx cosecx
= (2)^2 - 2
( because sinx cosecx = 1)
= 4 - 2
= 2
● hope it helps
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