Question

if sinx- cosx=0 find value of ( secx + cosecx)^2 is​

Answer 1

Answer:

Answer is 8

Step-by-step explanation:

sinx-cosx=0 when x=45

sec45=√2

cosec45=√2

= (sec45+cosec45)^2

=(√2+√2)^2

=(2√2)^2

=8

Answer 2

Answer:

okk

Step-by-step explanation:

sinx-cosx=0

sinx=cosx

tanx =1

x = 45°

then

( secx + cosecx)^2

(sec 45°+cosec45°)^2

(√2+√2)^2

(2√2)^2

4*2

8

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