if sinx+cosx=1 , then 3cosxsinx=?
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Answered by
1
Answer:
(sinx+cosx)^2=1^2
sin^2x+cos^2x+2sinx×cosx=1
1+2sinx×cosx =1
2sinx×cosx= 1-1
sinx×cosx=0
3sinx×cosx=0
3cosxsinx=0
riac57610:
thanks
Answered by
0
Answer:
0
Step-by-step explanation:
sinx + cosx= 1
(sinx+cosx)^2=1
sin^2 x +cos^2 x +2sinx cosx =1
2sinx cosx=0
3/2 sinxcosx=0
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