Question

If sinx+cosx=1, then sinx.cosx=?​

Answer 1

Answer:

0

Step-by-step explanation:

let x = 0

then sin0 = 0 and cos0 = 1

thus sin0 + cos0 = 1

and sin0 * cos0 = 0

another way:

$(sinx + cosx)^{2} = 1 \\sin^{2} x + cos^{2}x + 2.sinx.cosx= 1\\1 + 2sinx.cosx = 1 \\ 2sinx.cosx = 0\\sinx.cosx = 0$

because (sin^{2}x + cos^{2}x = 1 )

Answer 2

sinx+cosx=1.

squaring both sides.we get ,

(sinx+cosx)^2=(1)^2.

sin^2x+cos^2x+2sinx*cosx=1.

1+2sinx*cosx=1.

2sinx*cosx=1-1.

2sinx*cosx=0.

sinx*cosx=0.