if sinx + cosx =2 show that sinx^n + cosx^n =2
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sinx + cosx= 2
if we square both sides then
sin^2 x +cos^2 x +2sinxcosx = 4………(sin2x =2sinxcosx)
1 +sin2x =4
sin2x = 3 …….which is not possible so the question may be incorrect
the question can be like ;
sinx + cosy = 2 and we would have to find out sin^n x+cos^ny
in above problem it is possible only when sinx and cosx would have their maximum values so sinx= 1 and cosx=1
hence sin^n x +cos^n x= 1+1 =2
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