If sinx+cosx=a then |sinx-cosx|
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Answered by
1
Answer:
sinx+cosx=a
Now, (sinx+cosx)2+(sinx−cosx)2=2
⇒a2+(sinx−cosx)2=2
⇒(sinx−cosx)2=2−a2
⇒sinx−cosx=±2−a2−−−−−√
Hence, |sinx−cosx|=2−a2−−−−−√
Answered by
38
Answer:
sinx + cosx = a
squaring both sides
sin²x + cos²x +2sinxcosx = a²
2sinxcosx = a² - 1
(sinx - cosx )² = sin²x + cos²x - 2sinxcosx = 1 - (a² - 1) = 2-a²
|sinx-cosx| = √(2-a²)
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