If sinx + cosx÷ cos³costs = a tan³x + b tan²x +c tanx + d then a+b+c+d =
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Answered by
1
Answer:
Correct option is
C
4
cos
3
x
sinx+cosx
=atan
3
x+btan
2
x+ctanx+d
To find; a+b+c+d, Put, x=
4
π
We get,
=>
2
2
1
2
1
+
2
1
=a+b+c+d
=>
2
×2
2
=a+b+c+d
Hence,
=> a+b+c+d=4
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