Question

if sinx +cosx =m and secx+cosecx =n find n(m+1)(m-1)​

Answer 1

n(m+1)(m-1)

=(secx+cosecx)(sin^2x-cos^2x)

=(1/cosx+1/sinx)(sin^2x-cos^2x)

=((sinx-cosx)/sinx.cosx)(sin^2x - cos^2x)

=(sinx-cosx)(sinx+cosx)/sinx.cosx

Answer 2

This is a neat, stepwise solution for your doubt

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I hope this help you.