Question

If sinx + cosx =under root 2,then evaluate: tanx + cotx

Answer 1

sinx +cosx= √2
square both sides
1 + sin2x=2
sin2x=1
2x=π/2
x=π/4



we have to find
$\tan(x) + \cot(x) \\ since \: x \: = \pi \div 4 \\ \tan(\pi \div 4) + \cot(\pi \div 4) \\ = 1 + 1 \\ = 2$
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