Question

if sinx secx =-1 and x lie in 2nd quadrant find sin x and secx

Answer 1

$\sin(x). \sec(x) = - 1 \\ \\ \sin(x). \frac{1}{ \cos(x) } = - 1 \\ \\ \tan(x) = - 1 \\ \\ \\ x = \frac{\pi}{4} \\ \\ \\ \sin( \frac{\pi}{4} ) = \frac{1}{ \sqrt{2} } \\ \\ \\ \sec( \frac{\pi}{4} ) = - \sqrt{2}$