if sinx+sin²x=1,cos¹²x+3cos¹⁰x(3cos⁸x+3cos⁶x-2=
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ANSWER
Given: sinx+sin
2
x=1
sinx=1−sin
2
x=cos
2
x
Now,
cos
12
x+3cos
10
x+3cos
8
x+cos
6
x
⇒(cos
4
x)
3
+3(cos
4
x)
2
cos
2
x+3cos
4
x(cos
2
x)
2
+(cos
2
x)
3
⇒(sin
2
x)
3
+3sin
4
xcos
2
x+3sin
2
xcos
4
x+(cos
2
x)
3
⇒[sin
2
x+cos
2
x]
3
⇒1
3
⇒1.
solution
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