if sinx+sin2x=1 then cox+co2x=?
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Sinx + sin2x = 1
2 sin 3x/2 cos x/2 = 1
cos x/2 = 1 / (2 sin 3x/2 )
cos x + cos 2x = 2 cos x/2 cos 3x/2 substitute value of cos x/2 from above
= cos 3x/2 / sin 3x/2 = COT 3x/2
2 sin 3x/2 cos x/2 = 1
cos x/2 = 1 / (2 sin 3x/2 )
cos x + cos 2x = 2 cos x/2 cos 3x/2 substitute value of cos x/2 from above
= cos 3x/2 / sin 3x/2 = COT 3x/2
rohitduggal21:
put x=(pi/2) in the given equation..
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