If sinx + siny = 2sin(x+y) then show that tanx/2 tany/2 = 1/3
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Answer:
Step-by-step explanation:
Formula: sinA + sinB = 2sin(A+B)/2cos(A-B)/2
and sinA = 2sin(A/2)cos(A/2)
Given sinx + siny = 2sin(x+y),
=>2sin(x+y)/2cos(x-y)/2 = 2*2sin(x+y)/2cos(x+y)/2
=>cos(x-y)/2 = 2cos(x+y)/2
cos(x/2)cos(y/2) + sin(x/2)sin(y/2) =2( cos(x/2)cos(y/2) - sin(x/2)sin(y/2))
=>3 sin(x/2)sin(y/2) = cos(x/2)cos(y/2)
Dividing by cos(x/2)cos(y/2) on both sides, we get
Hence, tanx/2 tany/2 = 1/3
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