if (siny)^x = a , then find the value of dy/dx.
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Solution:-
given》
》 (siny)^x = a
》 take log both side
》 log(siny)^x = loga
》xlog.siny = loga
》 diffrenciation both side with respect to (x)
》x.1/siny.cosdy/dx + logsiny = 0
》 x.coty.dy/dx = -logsiny
》 dy/dx = (-log.siny)/ xcoty (answer )
i hope it is your helpfull for u
given》
》 (siny)^x = a
》 take log both side
》 log(siny)^x = loga
》xlog.siny = loga
》 diffrenciation both side with respect to (x)
》x.1/siny.cosdy/dx + logsiny = 0
》 x.coty.dy/dx = -logsiny
》 dy/dx = (-log.siny)/ xcoty (answer )
i hope it is your helpfull for u
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