if siny=x,cos(a+y)then dy/dx=?
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Answer:
If siny=xcos(a+y) , then (dy)/(dx) is equal to (a)(cos^2(a+y)
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Step-by-step explanation:
Given, sin y=xcos(a+y)
x=siny/cos(a+y)
differentiating with respect to y,
dx/dy=[cos(a+y)cosy-siny(-sin(a+y))]/cos²(a+y)
dx/dy=[cos(a+y)cosy+sinysin(a+y)]/cos²(a+y)
dx/dy=cos(a+y-y)/cos²(a+y)
dx/dy=cosa/cos²(a+y)
dy/dx=cos²(a+y)/cosa
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