If Sita gives an interest of Rs. 90 for two years at 9 % rate p. a. What is the sum she has borrowed?
Answers
Answer:
The sum borrowed is Rs.500.
Step-by-step explanation:
Given : If Meena gives an interest of Rs.45 for one year at 9% rate p.a.
To find : What is the sum she has borrowed ?
Solution :
Applying interest formula,
I=P\times R\times TI=P×R×T
Where, I=Rs.45 is the interest
R=9%=0.09 is the interest rate
T=1 year is the time
P is the principal or sum
Substitute the value in the formula,
45=P\times 0.09\times 145=P×0.09×1
P=\frac{45}{0.09}P=
0.09
45
P=500P=500
Therefore, The sum borrowed is Rs.500
Step-by-step explanation:
The sum borrowed is Rs.500.
Step-by-step explanation:
Given : If Meena gives an interest of Rs.45 for one year at 9% rate p.a.
To find : What is the sum she has borrowed ?
Solution :
Applying interest formula,
I=P\times R\times TI=P×R×T
Where, I=Rs.45 is the interest
R=9%=0.09 is the interest rate
T=1 year is the time
P is the principal or sum
Substitute the value in the formula,
45=P\times 0.09\times 145=P×0.09×1
P=\frac{45}{0.09}P=
0.09
45
P=500P=500
Therefore, The sum borrowed is Rs.500