if site of triangle are in ratio 3:4:5 and its perimeter is 24 cm find measure of each side of triangle
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Answer:
Let the sides be 3x, 4x and 5x
ATQ,
Perimeter of the triangle= 24cm
⇒3x+4x+5x=24 cm
⇒12x= 24cm
⇒x=2cm
Sides are 3*2,4*2 and 5*2 cm
Sides are 6cm, 8cm and 10 cm.
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Answered by
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Let the angles=x=>3x,4x,5x
Given:-
Perimeter of triangle=24cm
Perimeter=Side+Side+Side(Base+height+ perpendicular)
3x+4x+5x=24cm
12x=24
x=24/12
x=2
First angle=3x=3×2=6
Second angle=4x=4×2=8
Third angle=5x=5×2=10
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