Question

If size of atom(=1A^o) is enlarged to size of tip of sharp pin (=10^-5m) how large would be height of Mount Everest (=10^4m)

Answer 1

Given :

Size of an atom = 1 A°

Size of the tip of the sharp pin = 10⁻⁵ m

Original height of the Mount Everest = 10⁴ m

To Find :

The magnified height of the Mount Everest = ?

Solution :

• The size of an atom changes from 1 A° to 10⁻⁵ m

           $Magnification=\frac{10^{-5}}{10^{10}}$

• From the above relation,

            Height of the mountain  $=\frac{10^{-5}}{10^{10}}\times10^{4}$

                                                     $=10^{9}m$

The magnified height of the mount everest is 10⁹ m