Question

if slope of the line through [2, -7] and [x, 5] is 3 then x =

Answer 1

$\textbf{Given:}$

$\text{Points are (2,-7) and (x,5)}$

$\textbf{To find:}$

$\text{Slope of the line joining the given two points}$

$\textbf{Solution:}$

$\text{We know that,}$

$\text{Slope of the line joining (x_1,y_1) and (x_2,y_2) is}$

$=\bf\dfrac{y_2-y_1}{x_2-x_1}$

$\text{Slope of the line joining (2,-7) and (x,5) is 3}$

$\implies\dfrac{y_2-y_1}{x_2-x_1}=3$

$\implies\dfrac{5+7}{x-2}=3$

$\implies\dfrac{12}{x-2}=3$

$\implies\dfrac{4}{x-2}=1$

$\implies\,4=x-2$

$\implies\,4+2=x$

$\implies\boxd{\bf\,x=6}$

$\textbf{Answer:}$

$\textbf{The value of x is 6}$

Find more:

M and N are the two points on x axis and y axis repetitively P=(3,2) devide the line segment MN in ratio 2:3 find the coordinate of M and N and slope of line MN

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Find the slope of the line 2x + 5y - 11 = 0

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Answer 2

ANSWER ✔

$\large\underline\bold{GIVEN,}$

$\sf\dashrightarrow A(x_1,y_1)=(2,-7)$

$\sf\dashrightarrow B(x_2,y_2)=(x,5)$

$\sf\dashrightarrow x_1=2$

$\sf\dashrightarrow x_2=x$

$\sf\dashrightarrow y_1=-7$

$\sf\dashrightarrow y_2= 5$

$\large\underline\bold{TO\:FIND,}$

$\sf\dashrightarrow the\:value\:of\:x$

✯FORMULA IN USE,

$\large{\boxed{\bf{ \star\:\: slope= \dfrac{y_2-y_1}{x_2-x_1}\:\: \star}}}$

$\large\underline\bold{SOLUTION,}$

$\sf\therefore\text{ putting the values in the formula and solving it,}$

$\sf\dashrightarrow \dfrac{5-(-7)}{x-2} = 3$

$\sf\implies \dfrac{ 5+7}{x-2}= 3$

$\sf\implies \dfrac{ 12}{x-2}= 3$

$\sf\implies 12= 3 \times(x-2)$

$\sf\implies 12= 3x-6$

$\sf\implies 12+6=3x$

$\sf\implies 18= 3x$

$\sf\implies x= \dfrac{ 18}{3}$

$\sf\implies x=\cancel \dfrac{ 18}{3}$

$\sf\implies x=6$

$\large{\boxed{\bf{ \star\:\: x= 6\:\: \star}}}$

$\large\underline\bold{THE\:VALUE\:OF\:X\:IS\:6.}$

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