Question

If Sn=2+0.4n find initial velocity and acceleration ​

Answer 1

Answer:

We know distance traveled in n th second is given as S n = u+ f(2n−1)/2.

So comparing with given expression we get ,u+fn−f/2=2+0.4n 1

Now comparing the coefficients of n , we get f = 0.4 units  

and now put f=0.4  in equation-1 we get u=2.2units