Math, asked by Karekarshreeya28, 11 months ago

If Sn-3= n²+3n+4, find S. & hence find Tn.​

Answers

Answered by deviurmila017
1

Answer:

sn=n^2 +3n +7

Step-by-step explanation:

sn=n^2 +3n+7 ________ eq1

Sn-1 = (n-1)^2 +3(n-1)+7

= n^2+1-2n+3n-1+7

= n^2 +n+7 ____ eq 2

Tn=Sn-(Sn-1)

=n^2 + 3n + 7 -n^2 -n-7 (be eq1 and eq2)

= 2n

Tn= 2n

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