If Sn-3= n²+3n+4, find S. & hence find Tn.
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Answer:
sn=n^2 +3n +7
Step-by-step explanation:
sn=n^2 +3n+7 ________ eq1
Sn-1 = (n-1)^2 +3(n-1)+7
= n^2+1-2n+3n-1+7
= n^2 +n+7 ____ eq 2
Tn=Sn-(Sn-1)
=n^2 + 3n + 7 -n^2 -n-7 (be eq1 and eq2)
= 2n
Tn= 2n
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