If sn =3n+1 sn-1= 2n-1,then find the an
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Answer:
sn=3n+1
s1=3×1+1=4=a1
s2=3×2+1=7=a1+a2
S2-S1=a2=7-4=3
d=a2-a1=3-4=-1
an=a1+(n-1)d
=4+(n-1)(-1)
=4-n+1
=5-n
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