Question

if sn = (3n²-4n) , then find the nth term​

Answer 1

Plz check it once otherwise it should be correct

Answer 2

Answer:

Sn = ( 3n^2 -4n)

S1 = (3*1^2 - 4*1) = -1

a= -1

S2 = (3*2^2 -4*2) = 4

a2= S2-S1 = 4-(-1) = 5

d= a2-a1 = 5-(-1) = 6

d = 6

an = a +(n - 1 )d

= -1 +(n -1 )6

= -1 + 6n -6

= 6n -7

hence, the nth term is 6n -7.