Math, asked by vsachdeva514, 8 months ago

If Sn= 3n2 + 5n ; Find Tn ​

Answers

Answered by REDPLANET
2

Answer:

Given: Sn = 3n² + 5n

S₁ = 3(1)² + 5(1)  

= 3 + 5  

T₁ = 8

S₂ = 3(2)² + 5(2)

= 12 + 10

= 22

So, T₁ + T₂ = 22

8 + T₂ = 22

T₂ = 22 - 8

T₂ = 14

Now,

a = 8 and d = 14 - 8 = 6

∴ Tn = 8 + (n-1)6 = 6n +2

Answer = Tn = 6n + 2

Answered by akanksha2614
6

Answer:

Answer:

Given: Sn = 3n² + 5n

S₁ = 3(1)² + 5(1)

= 3 + 5

T₁ = 8

S₂ = 3(2)² + 5(2)

= 12 + 10

= 22

So, T₁ + T₂ = 22

8 + T₂ = 22

T₂ = 22 - 8

T₂ = 14

Now,

a = 8 and d = 14 - 8 = 6

∴ Tn = 8 + (n-1)6 = 6n +2

AnswerAnswer == TnTn == 6n6n ++ 22.

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