Question

if sn=3nsquare +4n then common difference is​

Answer 1

Sn = 3n2 + 4n

First term (a1) = S1 = 3(1)2 + 4(1) = 7

S2 = a1 + a2 = 3(2)2 + 4(2) = 20

a2 = 20 - a1 = 20 - 7 = 13

So, common difference (d) = a2 - a1 = 13 - 7 = 6

Answer 2

Step-by-step explanation:

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