Math, asked by jerrinsunil25, 9 months ago

If Sn=3nsquare +n find the AP

Answers

Answered by rishabhappbuilter210
3

Answer : Given : Sn=3n2+n

To find : the AP

S1 = 3 +2 = 5 Therefore t1 = 5

S2 = 3*2² +2*2 = 12 +4 = 16

d = 16 - 5 = 11

So AP is 5, 11 , 17 , 23, ... Answer

Tn = a + (n-1)d

= 5 + (n-1) 6

= 6n -1

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