if Sn=(4n+1) of an AP , find the AP
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4 , 4 , 4,.....n terms
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Harith
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sn=4n+1
s1=4+1=5
i.e. x1=5
s2=4×2+1=8+1=9
I.e. x2=9-5=4
d=4-5=-1
ap= 5,4,3,2,1,.....
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