Question

If Sn be the sum of n consecutive terms of an A.P. show that,
Sn+4 – 4Sn+3 + 6Sn+2 – 4Sn+2 + Sn = 0

Answer 1

Answer:

use the formula of sn

Sn=

$\frac{n}{2} (2a + (n - 1)d)$