If Sn denote the sum of the first n terms of an A.P. If S₂n = 3Sn, then S₃n : Sn is equal to
A. 4
B. 6
C. 8
D. 10
Answers
Answered by
4
B. 6
Step-by-step explanation:
Given: S₂n = 3Sn
Find S₃n : Sn
Solution:
We know that Sn = n(n+1)/2
So when S2n = 3Sn
2n(2n+1)/2 = 3n(n+1)/2
2(2n+1) = 3(n+1)
4n+2 = 3n+3
n = 1
Now S3n/Sn = [3n(3n+1)/2]/[n(n+1)/2]
= 3(3n+1)/ (n+1)
= 3*4 / 2
= 6
Option B is the answer.
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