If Sn denotes the sum of first n terms of an A.P., then S2-S1 is
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Question :- If Sn denotes the sum of first n terms of an A.P., then S2 - S1 is ?
Solution :-
Let ,
- a = first term of AP .
- d = common difference .
we know that,
- sum of n terms of an AP = (n/2)[2a + (n - 1)d]
So, we get,
→ S1 = (1/2)[2a + (1 - 1)d]
→ S1 = (1/2)[2a + 0d]
→ S1 = (1/2)[2a]
→ S1 = a .
Similarly,
→ S2 = (2/2)[2a + (2 - 1)d]
→ S2 = 1[2a + d]
→ S2 = (2a + d)
Therefore,
→ S2 - S1
→ (2a + d) - a
→ 2a - a + d
→ (a + d)
Or,
→ a + 1*d
→ a + (2 - 1)d
comparing with Tn = a + (n -1)d
→ (a2.) (Ans.)
Hence, (S2 - S1) is Equal to a2(second Term of AP.)
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