If Sn denotes the sum of n terms of an A.P., then Sn+3 - 3Sn+2 + 3Sn+1 - Sn is equal to ?
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hope it will help it is always 6
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andre12:
bro here option are -d, -a, 0, 2a
Answered by
1
Thank you for asking this question:
We know that Sn = n(n+1)/2
now it is given that
S2n = 3Sn
=> 2n(2n+1)/2 = 3n(n+1)/2
=> 2(2n+1) = 3(n+1)
=> 4n+2 = 3n+3
=> n = 1
then S3n/Sn = [3n(3n+1)/2]/[n(n+1)/2] = 3*4/1*2 = 6
If there is any confusion please leave a comment below.
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