Question

If Sn=. n^2, then find the value of Tn

Answer 1

Hey mates here is ur answer

Tn =Sn-Sn-1

Tn=n^2-(n-1)^2

Tn =n^2-n^2-1+2n

Tn=2n-1

ans

Answer 2

The value of $T_n=2n-1$.

Step-by-step explanation:

Given : The sum of n terms $S_n=n^2$.

To find : The value of $T_n$ ?

Solution :

$S_n=n^2$

Put n=n-1,

$S_{n-1}=(n-1)^2$

Using arithmetic regression properties,

$T_n=S_n-S_{n-1}$

Substitute the values,

$T_n=n^2-(n-1)^2$

$T_n=n^2-(n^2+1-2n)$

$T_n=n^2-n^2-1+2n$

$T_n=2n-1$

Therefore, the value of $T_n=2n-1$.

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