If sn = n² + 2n, then find first term & common difference?
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9
Answer:
for first term put n=1 that is equal to 3 and for common difference put n=2 that is 8 then common difference = 8-3=5
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Answered by
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Sn = n^2 + 2n
S(n-1) = (n-1)^2 + 2(n-1) = n^2 - 1
an = Sn - S(n-1) = n^2 + 2n - n^2 + 1 = 2n+1
First Term, a = 2*1 + 1 = 3
Second Term, a2 = 2*2 + 1 = 5
d = 5 - 3 = 2
Therefore
a = 3, d = 2 ——-> Answer
S(n-1) = (n-1)^2 + 2(n-1) = n^2 - 1
an = Sn - S(n-1) = n^2 + 2n - n^2 + 1 = 2n+1
First Term, a = 2*1 + 1 = 3
Second Term, a2 = 2*2 + 1 = 5
d = 5 - 3 = 2
Therefore
a = 3, d = 2 ——-> Answer
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