If Sn of the series 2n² + 1 then find tn?
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Step-by-step explanation:
The formula for the nth term is given by: Tn = a + (n − 1)d = dn + (a − d) (2) where a and d are fixed and n is the variable (integer ≥ 1). This corresponds to y = mx + b where m and b are fixed and x variable. Suppose we have a question that asks to find T21 given T5 and T9..
Hope its help..
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