If Sn, the sum of first n terms of an A.P. is given by Sn = 3n2 - 4n then find its nth term of ap
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S1= 3-4= -1 and S2 = 12-8= 4 ... .... a1 = -1 and d = 5 ... An = -1 + (n-1)5===-6+n
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