Chemistry, asked by tamannadeswal1098, 4 months ago

If solubility of CaCO3 is 0.03 g L- then solubility product of CaCO3 is
O 3 * 10-4
0 3.33 x 103
9 x 10-8
0 9​

Answers

Answered by junaid609khan
0

Answer:

CaCO

3

S

Ca

++

+

S

CO

3

−−

Let the solubility be S.

then,

Solubility product of electrolyte

K

sp

=[Ca

++

][CO

3

]

K

sp

=S

2

It is a binary electrolyte.

=(3.05×10

−4

)

2

⇒K

sp

=9.3×10

−8

Explanation:

hope it's help you

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