If solubility of CaCO3 is 0.03 g L- then solubility product of CaCO3 is
O 3 * 10-4
0 3.33 x 103
9 x 10-8
0 9
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Answer:
CaCO
3
→
S
Ca
++
+
S
CO
3
−−
Let the solubility be S.
then,
Solubility product of electrolyte
K
sp
=[Ca
++
][CO
3
−
]
K
sp
=S
2
It is a binary electrolyte.
=(3.05×10
−4
)
2
⇒K
sp
=9.3×10
−8
Explanation:
hope it's help you
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