Question

If solubility og any gas in the liquid at 1 bar pressure is 0.05 mol/l what will be its solubility at 3 bar

Answer 1

In this question we will apply Henry's law.

It states that :

At a constant temperature, the amount of a given gas dissolved in a given type and volume of liquid is directly proportional to the partial pressure of that gas in equilibrium with that liquid.

The relationship is given by :

p = kHc

Where :

p = the partial pressure of the solute above the solution

c = the concentration of the solute in the solution (in one of its many units)

kH = the Henry's Law constant, which has units such as L··atm/mol or atm/(mole fraction) or Pa · m3/mol

Substituting in the formulae :

P₁/P₂ = B₁/B₂

Where P =Pressure and B = the solubility

1/3 = 0.05/B₂

B₂ = 0.05 × 3 = 0.15mol/l