Question

if solution of h2so4 contains 80% by mass . specific gravity ( density ) of solution is 1.71 g/cc . find its molarity.

Answer 1

Percentage purity = 80%
Specific gravity = 1.71 g/ml
Equivalent weight of H2SO4 = 98/2 = 49 g-eq

Normality of H2SO4 =sp. gravity × 1000equivalent wt. × %purity Normality of H2SO4 = 1.71 ×100049× 0.80 =43.6224 N

Answer 2

Answer:

Therefore molarity is 27.91n

Explanation:

percentage of purity=80 percent

80grams of acid in 100g solution

specific gravity ( density ) of solution is 1.71 g/cc

or

density of solution=1.71g/ml

volume of solution=

$\frac{mass \: ofsolution}{density} \\ \\ = \frac{100g}{1.71 \frac{g}{ml} } \\ \\ = \frac{10000}{171} ml$

molar mass of acid mb=98g/mol

n.f of acid=2

normality or molarity given by formula

$molarity = \frac{n_{f} \times n_{b}}{v} \times 1 000$

$here \: n_{b} = \frac{w_{b}}{m_{b}} = \frac{80}{98}$

molarity is given by substituting all vales we get

$molarity = \frac{2 \times \frac{80}{98} }{ \frac{10000}{171} } = 27.91n$

Therefore molarity is 27.91n