If some money in compound interest doubled in 4 years in how many years will it be 8 times
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Let,
Principal = Rs. 100.
Amount = Rs. 200.
Rate = r%
Time = 4 years.
Now,
A = Px [1+ (r/100)]n;
200 = 100x [1+(r/100)]4;
2 = [1+(r/100)]4; . Equation (i)
If sum become 8 times in the time n years,
then,
8 = (1+(r/100))n;
Equation (ii)... (2)3 = (1+(r/100))n
Using eqn (i) in (ii), we get;
([1+(r/100)]4)3 = (1+(r/100))n;
[1+(r/100)]12 = (1+(r/100))n;
Thus, n = 12 years.
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