If some of 8terms of an AP is first term is 4 find 12th term
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Answer:
a12 = -7
Step-by-step explanation:
Given: S8=4=a
a12=?
We know that
Sn=n[2a+(n-1)d]/2
4=8[2×4+(8-1)d]/2
4×2=8[8+7d]
8=8[8+7d]
8+7d=1
7d=-7
d = -1
a=4, d= -1
Now, an=a+(n-1)d
∴a12=4+(12-1)(-1)= 4-11=-7
∴a12 = -7
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