if some of zeroes is 4 and product of zeroes in 5 form an equation
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a+b=4
a×b=5
the formula for the equation is
x^2-x(a+b)+a×b
x^2-4x+5
a×b=5
the formula for the equation is
x^2-x(a+b)+a×b
x^2-4x+5
laxman10201969:
The answer is right but there is something missing in the method
what is it ?
it's correct formula and the method is perfect
Do you wanted to write alpha and beta instead of a and b
it doesn't matter
a is used to represent the co efficient of x^2
And b is used to show the co efficient of x
but i represented a and b according to the formula which i have mentioned
Answered by
0
from the formula x²+(a+b)x + a x b
sum of zeroes = a+b = 4
product of zeroes =a x b = 5
now we can substitute the values,
x² - (4)x + 5
hence your equation is x²-4x+5
hope it helps you :)
if its helpful then plz mark it as brainliest
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