Math, asked by ashu123149paas8g, 1 year ago

If some of zeroes of f(x)=kx^2+2x+3k is equal to their product. find the value ok k

Answers

Answered by Anonymous

2

sum of the zeroes= -b/a = -2/k
products of zeroes = c /a = 3k/k
According to question..
-2/k = 3k/k
-2/k = 3
k = -2/3 ans .

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