Question

If someone can find the derivative of this function with details ^^ thx

Answer 1

Answer:

$-\frac{b}{(x+1)^2}-\frac{c}{(x+1)^{3}}$

Step-by-step explanation:

The given function is

$f(x)=a+\frac{b}{x+1}+\frac{c}{(x+1)^2}$

or, $f(x)=a+b(x+1)^{-1}+c(x+1)^{-2}$

Now the derivative of $f(x)$

$\frac{d}{dx}f(x)$

$=\frac{d}{dx}[a+b(x+1)^{-1}+c(x+1)^{-2}]$

$=\frac{d}{dx}a+\frac{d}{dx}b(x+1)^{-1}+\frac{d}{dx}c(x+1)^{-2}$

$=0+b(-1)(x+1)^{-2}+c(-2)(x+1)^{-3}$

$=-\frac{b}{(x+1)^2}-\frac{c}{(x+1)^{3}}$

Hope this helps.