Question

If specific rate constant for a first order reaction is 1 × 10–3 s–1 then the half-life period of the reaction will be 69.3 s 6.93 s 0.693 s 693 s

Answer 1

Answer:

693.15 sec

Explanation:

half life of first order is given by:

t = ln2/k

t = 0.692/1×10^-3

t = 693.147 sec