Question

if speed of a acar is increased by 20 km per hour it reaches its destination 2 hours earlier if the speed is further increased by 20 km per hour the car reaches the destination 3 hours earlier of the usual time what will be the speed of car if it reaches the destination 2 hours late​

Answer 1

Answer:

Step-by-step explanation:

Formula: Speed = Distance/ Time, Therefore, Time = Distance / speed

Given that speed of the car is 20km/hr more than the average speed of the bus, Let the speed of the bus be x,

Therefore speed of the car is x+20.

Average speed of the bus:

300/x - 4=300/x+20

=> 300[x+20-x/x(x+20)]= 4

=> 300(20/ x(x+20)) = 4

=> 300(20/x²+20x) = 4 (upon cross multiplying)

=> 6000= 4x²+80x

4x²+80x-6000=0

4(x² + 20x -1500) =0

x²+20x-1500=0

Upon factorizing,

(x+50)(x-30)=0

x=30

The bus goes 30 kmph; the car goes 50 kmph

Step-by-step explanation:

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