Physics, asked by iamt4582, 1 year ago

If speed of light is 3.00x10^8 m/s calculate the distance travelled by light in 2 ns

Answers

Answered by aryan2554
1

Answer:

V=f *lamda

3*10^8/2 = lamda

so, distance travelled by the wave=1.5*10^8.

Answered by Luckygautam
6

Answer:

0.600m

Explanation:

According to the question:

Time taken to cover the distance = 2.00 ns

= 2.00 × 10^–9 s

Speed of light = 3.0 × 10^8 ms–1

We know speed = distance/time

Or distance = speed x time

Therefore Distance travelled by light in 2.00 ns

= Speed of light × Time taken

= (3.0 × 10^8 ms –1) (2.00 × 10^–9 s)

= 6.00 × 10^–1 m

= 0.600 m

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