If speed of light is 3.00x10^8 m/s calculate the distance travelled by light in 2 ns
Answers
Answered by
1
Answer:
V=f *lamda
3*10^8/2 = lamda
so, distance travelled by the wave=1.5*10^8.
Answered by
6
Answer:
0.600m
Explanation:
According to the question:
Time taken to cover the distance = 2.00 ns
= 2.00 × 10^–9 s
Speed of light = 3.0 × 10^8 ms–1
We know speed = distance/time
Or distance = speed x time
Therefore Distance travelled by light in 2.00 ns
= Speed of light × Time taken
= (3.0 × 10^8 ms –1) (2.00 × 10^–9 s)
= 6.00 × 10^–1 m
= 0.600 m
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