Question

if speed of light is 3.0108/m then distance covered in 2ns is​

Answer 1

If the speed of light is 3.0 × 108ms-1, calculate the distance covered by light in 2.00 ns.

Explanation:

Answer:-

Distance covered = Speed×Time = 3.0 × 108ms-1 × 2.00 ns

= 3.0×108ms-1×2.00 ns×10-9s/1ns = 6.00×10-1m = 0.600m

Answer 2

Answer: multiply 3.01 ×2m/s then answer 6....01

Explanation: