If speed of particle at end of four successive hours is 20,25,30,35km/ hr then acceleration of particle is
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U=0
T=4 HRS
V=20,25,30 KM/HR
A=?
FROM THE EQUATION,V=U+AT,WE CAN GET ACCELERATION.
>20,25,30=0+AX4
>4A=20,25,30
>A=50,632.5 KM/HR²
AAYA SAMAJ.
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