Question

if speed of projection u is fixed then for what value of angle of projection , range will be maximum and also find out this maximum range.​

Answer 1

Answer:

45 degrees and $\frac{u^2}{g}$  is the maximum range

Explanation:

Initial velocity = u

Let the angle of projection be = x

Now, the formula for the range of a projectile is:

$R=\frac{u^2 sin(2x) }{g}$

Now, the maximum value of sin is 1 (and occurs at x=90 degrees)$Thus, 2x=90\\Hence, x=45 (degrees)$

Now, when x=45 degrees, the equation becomes:

$\frac{u^2 sin(2(45))}{g}\\i.e., \frac{u^2 sin(90))}{g}\\i.e., \frac{u^2}{g}$

Since, sin(90) = 1

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